b^2+8b+79=67

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Solution for b^2+8b+79=67 equation:


Simplifying
b2 + 8b + 79 = 67

Reorder the terms:
79 + 8b + b2 = 67

Solving
79 + 8b + b2 = 67

Solving for variable 'b'.

Reorder the terms:
79 + -67 + 8b + b2 = 67 + -67

Combine like terms: 79 + -67 = 12
12 + 8b + b2 = 67 + -67

Combine like terms: 67 + -67 = 0
12 + 8b + b2 = 0

Factor a trinomial.
(6 + b)(2 + b) = 0

Subproblem 1

Set the factor '(6 + b)' equal to zero and attempt to solve: Simplifying 6 + b = 0 Solving 6 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + b = 0 + -6 Combine like terms: 6 + -6 = 0 0 + b = 0 + -6 b = 0 + -6 Combine like terms: 0 + -6 = -6 b = -6 Simplifying b = -6

Subproblem 2

Set the factor '(2 + b)' equal to zero and attempt to solve: Simplifying 2 + b = 0 Solving 2 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + b = 0 + -2 b = 0 + -2 Combine like terms: 0 + -2 = -2 b = -2 Simplifying b = -2

Solution

b = {-6, -2}

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